30m^2+15m=0

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Solution for 30m^2+15m=0 equation:



30m^2+15m=0
a = 30; b = 15; c = 0;
Δ = b2-4ac
Δ = 152-4·30·0
Δ = 225
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{225}=15$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(15)-15}{2*30}=\frac{-30}{60} =-1/2 $
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(15)+15}{2*30}=\frac{0}{60} =0 $

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